Бесплатный урок с нашим репетитором!

Узнать подробнее

Новая Школа - онлайн-школа подготовки к ЕГЭ
При поддержке
Посмотреть все вопросы нейросети
Бесплатный пробный урок с репетитором

Узнай больше про репетиторов Новой Школы и запишись на бесплатный пробный урок. Мы проверим твой уровень знаний и составим план обучения по любому предмету и классу

Вопрос от Анонимного юзера 09 января 2025 16:37

X2-4x+3=0

Ответ нейросети

09 января 2025 16:37

To solve the quadratic equation (x^2 - 4x + 3 = 0), you can use the factoring method.

  1. Factoring: Look for two numbers that multiply to (3) (the constant term) and add to (-4) (the coefficient of (x)).

    The numbers (-1) and (-3) work because: (-1 \times -3 = 3) and (-1 + -3 = -4).

    Thus, you can factor the equation as: [ (x - 1)(x - 3) = 0 ]

  2. Setting each factor equal to zero: [ x - 1 = 0 \quad \text{or} \quad x - 3 = 0 ] This gives you: [ x = 1 \quad \text{or} \quad x = 3 ]

  3. Solutions: The solutions to the equation (x^2 - 4x + 3 = 0) are: [ x = 1 \quad \text{and} \quad x = 3 ]

You can verify these solutions by substituting them back into the original equation.

For (x = 1): [ (1)^2 - 4(1) + 3 = 1 - 4 + 3 = 0 ] For (x = 3): [ (3)^2 - 4(3) + 3 = 9 - 12 + 3 = 0 ]

Both solutions satisfy the equation, confirming that (x = 1) and (x = 3) are correct.

Задай свой вопрос

Напиши любую задачу или вопрос, а нейросеть её решит

Похожие вопросы 15

Бесплатно Мобильное приложение ГДЗ
Мобильное приложение ГДЗ

Задавай вопросы искуcственному интеллекту текстом или фотографиями в приложении на iPhone или Android

qr-codegoogle-playapp-store

Саша — ассистент в телеграмме

x2-4x+3=0
To solve the quadratic equation \(x^2 - 4x + 3 = 0\), you can use the factoring method. 1. **Factoring**: Look for two numbers that multiply to \(3\) (the constant term) and add to \(-4\) (the coefficient of \(x\)). The numbers \(-1\) and \(-3\) work because: \(-1 \times -3 = 3\) and \(-1 + -3 = -4\). Thus, you can factor the equation as: \[ (x - 1)(x - 3) = 0 \] 2. **Setting each factor equal to zero**: \[ x - 1 = 0 \quad \text{or} \quad x - 3 = 0 \] This gives you: \[ x = 1 \quad \text{or} \quad x = 3 \] 3. **Solutions**: The solutions to the equation \(x^2 - 4x + 3 = 0\) are: \[ x = 1 \quad \text{and} \quad x = 3 \] You can verify these solutions by substituting them back into the original equation. For \(x = 1\): \[ (1)^2 - 4(1) + 3 = 1 - 4 + 3 = 0 \] For \(x = 3\): \[ (3)^2 - 4(3) + 3 = 9 - 12 + 3 = 0 \] Both solutions satisfy the equation, confirming that \(x = 1\) and \(x = 3\) are correct.